staging: lustre: Convert uses of "int rc = seq_printf(...)"

staging: lustre: Convert uses of "int rc = seq_printf(...)"

The seq_printf return value, because it's frequently misused,
will eventually be converted to void.

See: commit 1f33c41c03da ("seq_file: Rename seq_overflow() to
     seq_has_overflowed() and make public")

Convert these uses to:

	seq_printf(seq, ...);

	return 0;

Done via cocci script:

@@
struct seq_file *seq;
int i;
@@
-	i = seq_printf(seq,
+	seq_printf(seq,
		   ...);
	...
-	return i;
+	return 0;

@@
struct seq_file *seq;
int i;
@@
-	i = 0;
-	i += seq_printf(seq,
+	seq_printf(seq,
	           ...);
	...
-	return i;
+	return 0;

With some additional reformatting and typing post conversion
to remove the now unnecessary "int i;" declaration.

Signed-off-by: Joe Perches <joe@perches.com>
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>