hbitmap: Fix merge when b is empty, and result is not an alias of a

Nobody calls the function like this currently, but we neither prohibit
or cope with this behavior. I decided to make the function cope with it.

Signed-off-by: John Snow <jsnow@redhat.com>
Reviewed-by: Max Reitz <mreitz@redhat.com>
Message-id: 20190709232550.10724-8-jsnow@redhat.com
Signed-off-by: John Snow <jsnow@redhat.com>

diff --git a/util/hbitmap.c b/util/hbitmap.c
index bcc0acdc6a011e1c4e168a2ce77527bd34ced409..83927f3c08ab5fa38c69dcd0526f3d20fc8f3857 100644 (file)
--- a/util/hbitmap.c
+++ b/util/hbitmap.c
@@ -785,8 +785,9 @@ bool hbitmap_can_merge(const HBitmap *a, const HBitmap *b)
 }
 
 /**
- * Given HBitmaps A and B, let A := A (BITOR) B.
- * Bitmap B will not be modified.
+ * Given HBitmaps A and B, let R := A (BITOR) B.
+ * Bitmaps A and B will not be modified,
+ *     except when bitmap R is an alias of A or B.
  *
  * @return true if the merge was successful,
  *         false if it was not attempted.
@@ -801,7 +802,13 @@ bool hbitmap_merge(const HBitmap *a, const HBitmap *b, HBitmap *result)
     }
     assert(hbitmap_can_merge(b, result));
 
-    if (hbitmap_count(b) == 0) {
+    if ((!hbitmap_count(a) && result == b) ||
+        (!hbitmap_count(b) && result == a)) {
+        return true;
+    }
+
+    if (!hbitmap_count(a) && !hbitmap_count(b)) {
+        hbitmap_reset_all(result);
         return true;
     }