On a 64bit Uml, if run under "setarch i386" (which a user did), uname()
currently returns the obtained i686 as machine - fix that.  Btw, I'm quite
surprised that under setarch i386 a 64-bit binary can run.
Cc: Andi Kleen <ak@suse.de>
Signed-off-by: Paolo 'Blaisorblade' Giarrusso <blaisorblade@yahoo.it>
Cc: Jeff Dike <jdike@addtoit.com>
Signed-off-by: Andrew Morton <akpm@osdl.org>
Signed-off-by: Linus Torvalds <torvalds@osdl.org>
        struct utsname host;
 
        uname(&host);
-#if defined(UML_CONFIG_UML_X86) && !defined(UML_CONFIG_64BIT)
+#ifdef UML_CONFIG_UML_X86
+# ifndef UML_CONFIG_64BIT
        if (!strcmp(host.machine, "x86_64")) {
                strcpy(machine_out, "i686");
                return;
        }
+# else
+       if (!strcmp(host.machine, "i686")) {
+               strcpy(machine_out, "x86_64");
+               return;
+       }
+# endif
 #endif
        strcpy(machine_out, host.machine);
 }