An L0 must invalidate the L2's RPT during H_GUEST_DELETE if this has not
already been done. This is a slow operation that means H_GUEST_DELETE
must return H_BUSY multiple times before completing. Invalidating the
tables before deleting the guest so there is less work for the L0 to do.
Signed-off-by: Jordan Niethe <jniethe5@gmail.com>
Signed-off-by: Michael Ellerman <mpe@ellerman.id.au>
Link: https://msgid.link/20231201132618.555031-2-vaibhav@linux.ibm.com
void kvmhv_vm_nested_init(struct kvm *kvm);
long kvmhv_set_partition_table(struct kvm_vcpu *vcpu);
long kvmhv_copy_tofrom_guest_nested(struct kvm_vcpu *vcpu);
+void kvmhv_flush_lpid(u64 lpid);
void kvmhv_set_ptbl_entry(u64 lpid, u64 dw0, u64 dw1);
void kvmhv_release_all_nested(struct kvm *kvm);
long kvmhv_enter_nested_guest(struct kvm_vcpu *vcpu);
kvmhv_set_ptbl_entry(kvm->arch.lpid, 0, 0);
}
- if (kvmhv_is_nestedv2())
+ if (kvmhv_is_nestedv2()) {
+ kvmhv_flush_lpid(kvm->arch.lpid);
plpar_guest_delete(0, kvm->arch.lpid);
- else
+ } else {
kvmppc_free_lpid(kvm->arch.lpid);
+ }
kvmppc_free_pimap(kvm);
}
}
}
-static void kvmhv_flush_lpid(u64 lpid)
+void kvmhv_flush_lpid(u64 lpid)
{
long rc;