sched/core: Remove TASK_ALL

It's unused:

  $ git grep "\<TASK_ALL\>" | wc -l
  1

... and it is also dangerous, kill the bugger.

Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org>
Signed-off-by: Sebastian Andrzej Siewior <bigeasy@linutronix.de>
Acked-by: Thomas Gleixner <tglx@linutronix.de>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Peter Zijlstra <peterz@infradead.org>
Link: http://lkml.kernel.org/r/20180227160510.10829-1-bigeasy@linutronix.de
Signed-off-by: Ingo Molnar <mingo@kernel.org>

diff --git a/include/linux/sched.h b/include/linux/sched.h
index b161ef8a902e6629444cb39d73de773721bef1d1..21b1168da9513659018134886f2f9c0b369f4ee7 100644 (file)
--- a/include/linux/sched.h
+++ b/include/linux/sched.h
@@ -93,7 +93,6 @@ struct task_group;
 
 /* Convenience macros for the sake of wake_up(): */
 #define TASK_NORMAL                    (TASK_INTERRUPTIBLE | TASK_UNINTERRUPTIBLE)
-#define TASK_ALL                       (TASK_NORMAL | __TASK_STOPPED | __TASK_TRACED)
 
 /* get_task_state(): */
 #define TASK_REPORT                    (TASK_RUNNING | TASK_INTERRUPTIBLE | \