Directly calling exit() prevents any kind of management or handling.
Instead use the corresponding runstate API.
The default behavior of the runstate API is the same as exit().
Signed-off-by: Thomas Weißschuh <thomas@t-8ch.de>
Reviewed-by: Philippe Mathieu-Daudé <philmd@linaro.org>
Message-ID: <
20240523-debugexit-v1-1-
d52fcaf7bf8b@t-8ch.de>
Signed-off-by: Philippe Mathieu-Daudé <philmd@linaro.org>
#include "hw/qdev-properties.h"
#include "qemu/module.h"
#include "qom/object.h"
+#include "sysemu/runstate.h"
#define TYPE_ISA_DEBUG_EXIT_DEVICE "isa-debug-exit"
OBJECT_DECLARE_SIMPLE_TYPE(ISADebugExitState, ISA_DEBUG_EXIT_DEVICE)
static void debug_exit_write(void *opaque, hwaddr addr, uint64_t val,
unsigned width)
{
- exit((val << 1) | 1);
+ qemu_system_shutdown_request_with_code(SHUTDOWN_CAUSE_GUEST_SHUTDOWN,
+ (val << 1) | 1);
}
static const MemoryRegionOps debug_exit_ops = {