ARM: use MiB for vmalloc sizes

Rather than using "m" (which is the unit of metres, or milli), and
"MB" in the printk statements, use MiB to make it clear that we are
talking about the power-of-2 megabytes, aka mebibytes.

Reviewed-by: Linus Walleij <linus.walleij@linaro.org>
Reviewed-by: Yanfei Xu <yanfei.xu@windriver.com>
Signed-off-by: Russell King (Oracle) <rmk+kernel@armlinux.org.uk>

diff --git a/arch/arm/mm/mmu.c b/arch/arm/mm/mmu.c
index f2741cfc3951fbb580a56eaca2dfc69232ba46e0..09ac15c6d984998dd44d30a6a3efc42dd026695d 100644 (file)
--- a/arch/arm/mm/mmu.c
+++ b/arch/arm/mm/mmu.c
@@ -1126,7 +1126,7 @@ static unsigned long __initdata vmalloc_size = 240 * SZ_1M;
 /*
  * vmalloc=size forces the vmalloc area to be exactly 'size'
  * bytes. This can be used to increase (or decrease) the vmalloc
- * area - the default is 240m.
+ * area - the default is 240MiB.
  */
 static int __init early_vmalloc(char *arg)
 {
@@ -1135,14 +1135,14 @@ static int __init early_vmalloc(char *arg)
 
        if (vmalloc_reserve < SZ_16M) {
                vmalloc_reserve = SZ_16M;
-               pr_warn("vmalloc area too small, limiting to %luMB\n",
+               pr_warn("vmalloc area is too small, limiting to %luMiB\n",
                        vmalloc_reserve >> 20);
        }
 
        vmalloc_max = VMALLOC_END - (PAGE_OFFSET + SZ_32M + VMALLOC_OFFSET);
        if (vmalloc_reserve > vmalloc_max) {
                vmalloc_reserve = vmalloc_max;
-               pr_warn("vmalloc area is too big, limiting to %luMB\n",
+               pr_warn("vmalloc area is too big, limiting to %luMiB\n",
                        vmalloc_reserve >> 20);
        }