virtiofs: drop __exit from virtio_fs_sysfs_exit()

virtio_fs_sysfs_exit() is called by:
- static int __init virtio_fs_init(void)
- static void __exit virtio_fs_exit(void)

Remove __exit from virtio_fs_sysfs_exit() since virtio_fs_init() is not
an __exit function.

Reported-by: kernel test robot <lkp@intel.com>
Closes: https://lore.kernel.org/oe-kbuild-all/202402270649.GYjNX0yw-lkp@intel.com/
Signed-off-by: Stefan Hajnoczi <stefanha@redhat.com>
Reviewed-by: Randy Dunlap <rdunlap@infradead.org>
Tested-by: Randy Dunlap <rdunlap@infradead.org> # build-tested
Signed-off-by: Miklos Szeredi <mszeredi@redhat.com>

diff --git a/fs/fuse/virtio_fs.c b/fs/fuse/virtio_fs.c
index 62a44603740c0abcb7f1ec7db3f633e9205cb539..948b49c2460dc4ed66591c687b32dbeff1d3477d 100644 (file)
--- a/fs/fuse/virtio_fs.c
+++ b/fs/fuse/virtio_fs.c
@@ -1588,7 +1588,7 @@ static int __init virtio_fs_sysfs_init(void)
        return 0;
 }
 
-static void __exit virtio_fs_sysfs_exit(void)
+static void virtio_fs_sysfs_exit(void)
 {
        kset_unregister(virtio_fs_kset);
        virtio_fs_kset = NULL;