From: Filipe Manana Date: Wed, 13 Apr 2022 15:20:42 +0000 (+0100) Subject: btrfs: return block group directly at btrfs_next_block_group() X-Git-Url: http://git.maquefel.me/?a=commitdiff_plain;h=8b01f931c140a943e837d86a9b82f0910629492e;p=linux.git btrfs: return block group directly at btrfs_next_block_group() At btrfs_next_block_group(), we have this long line with two statements: cache = btrfs_lookup_first_block_group(...); return cache; This makes it a bit harder to read due to two statements on the same line, so change that to directly return the result of the call to btrfs_lookup_first_block_group(). Reviewed-by: Nikolay Borisov Signed-off-by: Filipe Manana Reviewed-by: David Sterba Signed-off-by: David Sterba --- diff --git a/fs/btrfs/block-group.c b/fs/btrfs/block-group.c index 2c42ce00b84d4..db112a01d7113 100644 --- a/fs/btrfs/block-group.c +++ b/fs/btrfs/block-group.c @@ -271,7 +271,7 @@ struct btrfs_block_group *btrfs_next_block_group( read_unlock(&fs_info->block_group_cache_lock); btrfs_put_block_group(cache); - cache = btrfs_lookup_first_block_group(fs_info, next_bytenr); return cache; + return btrfs_lookup_first_block_group(fs_info, next_bytenr); } node = rb_next(&cache->cache_node); btrfs_put_block_group(cache);